Construction Management: "Time Cost Trade-off"
Time Cost Trade-off
Time Cost Trade-off
Time - Cost Trade-off Analysis, Why do project managers require this?
Total project costs include both direct costs and indirect costs of performing the activities of the project.
If each activity of the project is scheduled for the duration that results in the minimum direct cost (normal duration) then the time to complete the entire project might be too long and substantial penalties associated with the late project completion might be incurred.
At the other extreme, a manager might choose to complete the activity in the minimum possible time, called crash duration, but at a maximum cost.
Thus, planners perform what is called time cost trade-off analysis to shorten the project duration.
This can be done by selecting some activities on the critical path to shorten their duration. As the direct cost for the project equals the sum of the direct costs of its activities, then the project direct cost will increase by decreasing its duration. On the other hand, the indirect cost will decrease by decreasing the project duration, as the indirect cost are almost a linear function with the project duration.
The expenditures which cannot be allotted clearly to the
individual activities of the project, but are assessed as a whole are called
indirect costs. The indirect cost includes overhead charges, administrative and
establishment charges, supervision charges, loss of revenue, loss in profit and
penalty, etc. Indirect cost is directly proportional to the time. (Refer figure 'b' below)
Total Cost:
The combinations of direct cost and indirect cost is the total cost. The sum of direct costs and indirect costs is known as the total costs of the project. The relationship between indirect costs, direct cost and total cost with duration is given in the figure 'c' below. From the figure, it is seen that the curve of direct costs does not have a linear relationship with time. Thus the combination of direct and indirect cost gives a curvilinear relationship with time as shown.
From the total cost curve ACB, it is seen that the total cost of a project is minimum for a certain time duration. This duration is known as optimum duration (To) for the corresponding minimum cost (Cm). Further, if the project duration is increased, the total cost will also increase. On the other hand, if the project duration is decreased to the crash value, the project cost will be the highest. The optimum duration is less than the normal duration (Tn) corresponding to the direct costs.
This is because both direct and indirect cost increases beyond the normal duration, whereas below the normal duration indirect cost decrease, but the direct cost increases.
Direct and Indirect cost in Rate Analysis
Normal time (Tn)
The time usually allowed for an activity by the estimator is
known as normal time. It is the standard time for that activity and is denoted
by Tn.
Crash time (Tc)
The minimum possible time in which an activity can be
completed by deploying extra resources is known as crash time. Beyond the crash
time, the duration of an activity cannot be reduced or shortened by any amount
of increase in mobilization. It is denoted by Tc.
Normal cost (Cn)
The direct cost required to complete the activity in the
normal duration is called normal cost and is denoted by Cn.
Crash cost (Cc)
The direct cost corresponding to the crash time of
completing an activity is known as crash cost and is denoted by Cc.
Cost slope (C.S)
The
direct cost curve generally is a curve as shown below. But this curve can be
approximated by the straight line or more than one straight lines depending
upon the flatness of the curve. Thus the slope of this straight line is cost
slope. (Refer figure 'e' below)
Note: To crash the activity duration from normal time (Tn) to Crash time (Tc), we have to expense an extra resources in addition to Normal cost (Cn). without spending extra resources in direct cost, an activity cannot be reduced to crash duration.
Cost optimization through network (Steps in Optimization of Cost)
- First, draw the network diagram and find out all the
possible paths. Critical path and non-critical paths. Critical path
duration is the normal project duration for that project
- Calculate the direct cost by adding the normal cost
of all activities. Calculate indirect cost by multiplying project duration
with the indirect cost (overhead or indirect expense) per unit time
- Calculate the total cost by adding direct cost and
indirect cost. This total cost is the baseline cost for the calculation.
Similarly, the longest duration (critical path duration) is the project
duration as a baseline duration for the calculation.
- Calculate the cost slopes of all activities and rank
them in ascending order of cost slopes.
- Start crashing the project from a critical path
(since this is the project duration) by selecting such critical activity
having least cost slope as per ranking to the maximum possible extent
(observe other non-critical paths which are likely to be critical)
- Calculate the direct cost by adding the extra cost of crashing (cost slope * (Tn-Tc)) required for crashing that activity to the direct cost calculated in previous steps and corresponding indirect cost of reduced project duration.
After step six, three possible cases may arise:
Case I: If the same path remains critical (longest) then crashing is considered for
the critical activity serially in the ascending order to their cost slope as
far as possible.
Case II: While crashing the critical path, there may emerge a new critical path/s
then crashing is carried out for the common activity. If there is more than one
common activity, activity with the least cost slope is selected first and
continues serially as per the ranking of cost slopes.
Case III: After crashing as per the case II, if there is a
possibility of crashing then, one activity from each path is selected at one
time for crashing. This crashing is known as simultaneous crashing or parallel
crashing. The process is continued until the project shortening is possible.
Note:
Every time after crashing, the direct cost and
indirect cost is calculated to find out the total cost. If the total cost
calculated after crashing is greater than the earlier step, we come to the end
of optimization.
Whereas, for the determination of minimum possible
time (Tm), crashing should be continued until the possibility.
Activity |
Normal duration (Tn) |
Normal cost (Cn) |
Crash duration (Tc) |
Crash cost (Cc) |
A B C D E |
7 9 5 6 6 |
8000 5000 7000 9000 6000 |
4 6 2 4 4 |
15500 9500 10000 16000 12000 |
Figure: Network Diagram for above question
Here, The path A – C – E is critical path with the project duration equals to 18 Weeks
Project Cost:
Direct cost of the project = Summation of Normal cost of all activities = å normal cost = 35000
Indirect project cost of project = project duration * Indirect cost per week = 18 × 3150 = 5670
\ Total project cost = 91700
This shows that the total project cost is Cn= 91700 for Tn = 18 weeks of normal project duration
Calculation of Cost Slopes:
Activity |
Difference in cost (Crash
cost- normal cost) |
Difference in duration (Normal
duration - crash duration) |
Cost slope = Cc-Cn/Tn-Tc |
Ranking in ascending order |
A B C D E |
7500 4500 3000 7000 6000 |
3 3 3 2 2 |
2500 1500 1000 3500 3000 |
3 2 1 5 4 |
Revised Project duration
Revised Project Cost
Extra cost of crashing activity E by 2 weeks = 2 × 3000 = 6000
Direct cost = 6000 + 38000 = 44000
Indirect cost = 13 × 3150 = 40950
Total cost = 84950
Note: Here the total project cost is less than the total cost calculated in earlier step, hence further optimization is required.
After Crashing activity E, here we find that all paths become critical at this stage with project duration\
equal to 13weeks. This emerge the case - III
Simultaneous crashing: Now, Selecting 'A' from path A – D and A – C – E to crash and simultaneously
selecting activity 'B' from path B – E. Activity 'A' is selected due to common for both paths A – D and
A – C – E. So, crashing activities 'A' and 'B' by 3 weeks simultaneously we get. (Note: always select
equal duration for crashing while crashing activities simultaneously)
Note: Here the total cost amounting 87500 is greater than the cost amounting 84950 calculated in earlier step. This shows the end of cost optimization.
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